In the reaction,the acid obtained will be
$CH_3CHO + HCN \to CH_3CH(OH)CN \xrightarrow{H_2O} CH_3CH(OH)COOH$

  • A
    $D$-isomer
  • B
    $L$-isomer
  • C
    $(80\% \,D + 20\% \,L)$ mixture
  • D
    $(50\% \,D + 50\% \,L)$ mixture

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